C#程序：计算输入数字中1的个数

int[] num = new int[] {1, 25, 1, 55, 1};

Now loop through and find for 1, if 1 is there, 6 then increment the variable that counts the occurrence −

foreach(int j in num) {
if (j == 1) {
cal++;
}
}

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Example

The following is the code to count the number of 1’s in the entered number.

Live Demo

using System;
public class Demo {
public static void Main() {
int cal = 0;
int[] num = new int[] {1, 25, 1, 55, 1};
Console.WriteLine("Numbers:");
for (int i = 0; i < 5; i++) {
Console.WriteLine(num[i]);
}
foreach (int j in num) {
if (j == 1) {
cal++;
}
}
Console.WriteLine("Number of 1's: ");
Console.WriteLine(cal);
Console.ReadLine();
}
}

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Output

Numbers:
1
25
1
55
1
Number of 1's:
3

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