输入一个字符串，找到单词的总数、元音字母的数量和用户输入的字符的频率
Input : enter s string : I love my MOM
Enter a charcter of which you want to find a frequency: M
Total frequency of M : 2
Total number of vowels : 4
Total number of words : 4
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算法
START
Step 1 Declare array of string, ch, i, freq to 0, vow to 0, word to 0
Step 2 Input a string and a character ch
Step 3 Loop for from i to 0 and str[i]!=’o’ and ++i
Step 3.1 IF statement for ch==str[i]
Post incrementing freq
Step 3.2 End If
Step 3.3 IF statement
str[i]=='a'||str[i]=='e'||str[i]=='i'||str[i]=='o'||str[i]=='u'||str[i]=='A'||str[i]=='E'||str[i]=='I'||str[i]=='O'||str[i]=='U'
Post incrementing vow
Step 3.4 End If
Step 3.5 IF statement str[i]=’ ’
Post incrementing word
Step 3.6 End If
Step 4 End For loop
STOP
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Example
#include
int main() {
char str[1000], ch;
int i, freq=0, vow=0, word=0;
printf("Enter a string of your choice: ");
gets(str);
printf("Enter a character of which you want to find the frequency: ");
scanf("%c",&ch);
for(i = 0; str[i] != ' '; ++i){
if(ch == str[i]) //to find the frequency of a character {
++freq;
}
if(str[i]=='a'||str[i]=='e'||str[i]=='i'||str[i]=='o'||str[i]=='u'||str[i]=='A'||str[i]=='E'||str[i]=='I'||str[i]=='O'||str[i]=='U') {
++vow; //to find the number of vowels
}
if (str[i] == ' ') {
word++; //to find the number of words
}
}
printf("Frequency of %c = %d", ch, freq);
printf("
total number of vowels in a string are %d " ,vow );
printf("
total number of words in a string are %d " ,word+1 );
return 0;
}
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输出
如果我们运行上面的程序，它将生成以下输出。
Enter a string of your choice: I love PrograMMIng
Enter a character of which you want to find the frequency: M
Frequency of M = 2
total number of vowels in a string are 6
total number of words in a string are 3
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