以查询前20到30条为例,主键名为id 方法一: 先正查,再反查 select top 10 * from (select top 30 * from tablename order by id asc) A order by id desc 方法二: 使用left join select top 10 A.* from tablename A left outer joi
以查询前20到30条为例,主键名为id 方法一: 先正查,再反查 select top 10 * from (select top 30 * from tablename order by id asc) A order by id desc 方法二: 使用left join select top 10 A.* from tablename A left outer join (select top 20 * from tablename order by id asc) B on A.id = B.id where B.id is null order by A.id asc 方法三: 使用not exists select top 10 * from tablename A where id not exists (select top 20 * from tablename B on A.id = B.id) 方法四: 使用not in select top 10 * from tablename where id not in (select top 20 id from tablename order by id asc) order by id asc 方法五: 使用rank() select id from (select rank() over(order by id asc) rk, id from tablename) T where rk between 20 and 30 中第五种方法看上去好像没有问题,查了下文档,当over()用于rank/row_number时,整型列不能描述一个列,所以会产生非预期的效果. 待考虑下,有什么办法可以修改为想要的结果.
