MySQL 查找价格最高的图书经销商的几种SQL语句

2023年 4月 19日 33.8k 0

mysql use test; Database changed mysql CREATE TABLE shop ( - article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL, - dealer CHAR(20) DEFAULT '' NOT NULL, - price DOUBLE(16,2) DEFAULT '0.00' NOT NULL, - PRIMARY KEY(article, dealer)); Que

mysql> use test; Database changed mysql> CREATE TABLE shop ( -> article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL, -> dealer CHAR(20) DEFAULT '' NOT NULL, -> price DOUBLE(16,2) DEFAULT '0.00' NOT NULL, -> PRIMARY KEY(article, dealer)); Query OK, 0 rows affected (0.13 sec) mysql> INSERT INTO shop VALUES -> (1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45), -> (3,'C',1.69),(3,'D',1.25),(4,'D',19.95); Query OK, 7 rows affected (0.03 sec) Records: 7 Duplicates: 0 Warnings: 0 mysql> select * from shop; +---------+--------+-------+ | article | dealer | price | +---------+--------+-------+ | 0001 | A | 3.45 | | 0001 | B | 3.99 | | 0002 | A | 10.99 | | 0003 | B | 1.45 | | 0003 | C | 1.69 | | 0003 | D | 1.25 | | 0004 | D | 19.95 | +---------+--------+-------+ 7 rows in set (0.06 sec) mysql> select article,max(price) from shop group by article -> ; +---------+------------+ | article | max(price) | +---------+------------+ | 0001 | 3.99 | | 0002 | 10.99 | | 0003 | 1.69 | | 0004 | 19.95 | +---------+------------+ 4 rows in set (0.05 sec) mysql> select article,max(price),dealer from shop group by article; +---------+------------+--------+ | article | max(price) | dealer | +---------+------------+--------+ | 0001 | 3.99 | A | | 0002 | 10.99 | A | | 0003 | 1.69 | B | | 0004 | 19.95 | D | +---------+------------+--------+ 4 rows in set (0.00 sec) mysql> select article,dealer,price from shop s1 -> where price=(select max(s2.price) from shop s2 -> where s1.article=s2.article); +---------+--------+-------+ | article | dealer | price | +---------+--------+-------+ | 0001 | B | 3.99 | | 0002 | A | 10.99 | | 0003 | C | 1.69 | | 0004 | D | 19.95 | +---------+--------+-------+ 4 rows in set (0.01 sec) mysql> select s1.article,dealer,s1.price -> from shop s1 -> join( -> select article,max(price) as price from shop -> group by article) as s2 -> on s1.article = s2.article and s1.price = s2.price; +---------+--------+-------+ | article | dealer | price | +---------+--------+-------+ | 0001 | B | 3.99 | | 0002 | A | 10.99 | | 0003 | C | 1.69 | | 0004 | D | 19.95 | +---------+--------+-------+ 4 rows in set (0.05 sec) mysql> select s1.article,s1.dealer,s1.price from shop s1 -> left join shop s2 on s1.article=s2.article and s1.price select s1.article,s1.dealer,s1.price,s2.* from shop s1 left join shop s2 on s1.article=s2.article and s1.price

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