如何通过SQL找出2个表里值不同的列的方法
以下有两个表，他们的结构完全相同，请通过SQL找出值不同的列。 Student_1 NAME AGE SCORE peter 26 100 jack 25 96 daniel 26 48 bark 21 69 Student_2 NAME AGE SCORE peter 26 89 jack 25 96 daniel 26 48 bark 21 69 方法一
以下有两个表，他们的结构完全相同，请通过SQL找出值不同的列。
Student_1
NAME AGE SCORE peter 26 100 jack 25 96 daniel 26 48 bark 21 69
Student_2
NAME AGE SCORE peter 26 89 jack 25 96 daniel 26 48 bark 21 69
方法一 -- NOT EXISTS：复制代码 代码如下:SELECT *FROM Student_1 S1WHERE NOT EXISTS (SELECT * FROM Student_2 S2 WHERE S1.name = S2.name AND S1.age = S2.age AND S1.score = S2.score )UNION ALLSELECT *FROM STUDENT_2 S2WHERE NOT EXISTS (SELECT * FROM STUDENT_1 S1 WHERE S1.name = S2.name AND S1.age = S2.age AND S1.score = S2.score );
方法二 -- MINUS复制代码 代码如下:(SELECT * FROM Student_1MINUSSELECT * FROM Student_2)UNION ALL(SELECT * FROM Student_2MINUSSELECT * FROM Student_1)
方法三 -- HAVING GROUP BY复制代码 代码如下:SELECT DISTINCT name, age, score FROM (SELECT * FROM Student_1UNION ALLSELECT * FROM Student_2)GROUP BY name, age, score HAVING COUNT(*)=1 ;
